Optimal. Leaf size=147 \[ \frac{2 \sqrt{d+e x} \left (c d^2-a e^2\right )^2}{c^3 d^3}+\frac{2 (d+e x)^{3/2} \left (c d^2-a e^2\right )}{3 c^2 d^2}-\frac{2 \left (c d^2-a e^2\right )^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{d} \sqrt{d+e x}}{\sqrt{c d^2-a e^2}}\right )}{c^{7/2} d^{7/2}}+\frac{2 (d+e x)^{5/2}}{5 c d} \]
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Rubi [A] time = 0.0917097, antiderivative size = 147, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 37, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.108, Rules used = {626, 50, 63, 208} \[ \frac{2 \sqrt{d+e x} \left (c d^2-a e^2\right )^2}{c^3 d^3}+\frac{2 (d+e x)^{3/2} \left (c d^2-a e^2\right )}{3 c^2 d^2}-\frac{2 \left (c d^2-a e^2\right )^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{d} \sqrt{d+e x}}{\sqrt{c d^2-a e^2}}\right )}{c^{7/2} d^{7/2}}+\frac{2 (d+e x)^{5/2}}{5 c d} \]
Antiderivative was successfully verified.
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Rule 626
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(d+e x)^{7/2}}{a d e+\left (c d^2+a e^2\right ) x+c d e x^2} \, dx &=\int \frac{(d+e x)^{5/2}}{a e+c d x} \, dx\\ &=\frac{2 (d+e x)^{5/2}}{5 c d}+\frac{\left (c d^2-a e^2\right ) \int \frac{(d+e x)^{3/2}}{a e+c d x} \, dx}{c d}\\ &=\frac{2 \left (c d^2-a e^2\right ) (d+e x)^{3/2}}{3 c^2 d^2}+\frac{2 (d+e x)^{5/2}}{5 c d}+\frac{\left (c d^2-a e^2\right )^2 \int \frac{\sqrt{d+e x}}{a e+c d x} \, dx}{c^2 d^2}\\ &=\frac{2 \left (c d^2-a e^2\right )^2 \sqrt{d+e x}}{c^3 d^3}+\frac{2 \left (c d^2-a e^2\right ) (d+e x)^{3/2}}{3 c^2 d^2}+\frac{2 (d+e x)^{5/2}}{5 c d}+\frac{\left (c d^2-a e^2\right )^3 \int \frac{1}{(a e+c d x) \sqrt{d+e x}} \, dx}{c^3 d^3}\\ &=\frac{2 \left (c d^2-a e^2\right )^2 \sqrt{d+e x}}{c^3 d^3}+\frac{2 \left (c d^2-a e^2\right ) (d+e x)^{3/2}}{3 c^2 d^2}+\frac{2 (d+e x)^{5/2}}{5 c d}+\frac{\left (2 \left (c d^2-a e^2\right )^3\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{c d^2}{e}+a e+\frac{c d x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{c^3 d^3 e}\\ &=\frac{2 \left (c d^2-a e^2\right )^2 \sqrt{d+e x}}{c^3 d^3}+\frac{2 \left (c d^2-a e^2\right ) (d+e x)^{3/2}}{3 c^2 d^2}+\frac{2 (d+e x)^{5/2}}{5 c d}-\frac{2 \left (c d^2-a e^2\right )^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{d} \sqrt{d+e x}}{\sqrt{c d^2-a e^2}}\right )}{c^{7/2} d^{7/2}}\\ \end{align*}
Mathematica [A] time = 0.112306, size = 135, normalized size = 0.92 \[ \frac{2 \sqrt{d+e x} \left (15 a^2 e^4-5 a c d e^2 (7 d+e x)+c^2 d^2 \left (23 d^2+11 d e x+3 e^2 x^2\right )\right )}{15 c^3 d^3}-\frac{2 \left (c d^2-a e^2\right )^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{d} \sqrt{d+e x}}{\sqrt{c d^2-a e^2}}\right )}{c^{7/2} d^{7/2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.194, size = 324, normalized size = 2.2 \begin{align*}{\frac{2}{5\,cd} \left ( ex+d \right ) ^{{\frac{5}{2}}}}-{\frac{2\,a{e}^{2}}{3\,{c}^{2}{d}^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}+{\frac{2}{3\,c} \left ( ex+d \right ) ^{{\frac{3}{2}}}}+2\,{\frac{{a}^{2}{e}^{4}\sqrt{ex+d}}{{c}^{3}{d}^{3}}}-4\,{\frac{a{e}^{2}\sqrt{ex+d}}{{c}^{2}d}}+2\,{\frac{d\sqrt{ex+d}}{c}}-2\,{\frac{{a}^{3}{e}^{6}}{{c}^{3}{d}^{3}\sqrt{ \left ( a{e}^{2}-c{d}^{2} \right ) cd}}\arctan \left ({\frac{\sqrt{ex+d}cd}{\sqrt{ \left ( a{e}^{2}-c{d}^{2} \right ) cd}}} \right ) }+6\,{\frac{{a}^{2}{e}^{4}}{{c}^{2}d\sqrt{ \left ( a{e}^{2}-c{d}^{2} \right ) cd}}\arctan \left ({\frac{\sqrt{ex+d}cd}{\sqrt{ \left ( a{e}^{2}-c{d}^{2} \right ) cd}}} \right ) }-6\,{\frac{ad{e}^{2}}{c\sqrt{ \left ( a{e}^{2}-c{d}^{2} \right ) cd}}\arctan \left ({\frac{\sqrt{ex+d}cd}{\sqrt{ \left ( a{e}^{2}-c{d}^{2} \right ) cd}}} \right ) }+2\,{\frac{{d}^{3}}{\sqrt{ \left ( a{e}^{2}-c{d}^{2} \right ) cd}}\arctan \left ({\frac{\sqrt{ex+d}cd}{\sqrt{ \left ( a{e}^{2}-c{d}^{2} \right ) cd}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.95522, size = 771, normalized size = 5.24 \begin{align*} \left [\frac{15 \,{\left (c^{2} d^{4} - 2 \, a c d^{2} e^{2} + a^{2} e^{4}\right )} \sqrt{\frac{c d^{2} - a e^{2}}{c d}} \log \left (\frac{c d e x + 2 \, c d^{2} - a e^{2} - 2 \, \sqrt{e x + d} c d \sqrt{\frac{c d^{2} - a e^{2}}{c d}}}{c d x + a e}\right ) + 2 \,{\left (3 \, c^{2} d^{2} e^{2} x^{2} + 23 \, c^{2} d^{4} - 35 \, a c d^{2} e^{2} + 15 \, a^{2} e^{4} +{\left (11 \, c^{2} d^{3} e - 5 \, a c d e^{3}\right )} x\right )} \sqrt{e x + d}}{15 \, c^{3} d^{3}}, -\frac{2 \,{\left (15 \,{\left (c^{2} d^{4} - 2 \, a c d^{2} e^{2} + a^{2} e^{4}\right )} \sqrt{-\frac{c d^{2} - a e^{2}}{c d}} \arctan \left (-\frac{\sqrt{e x + d} c d \sqrt{-\frac{c d^{2} - a e^{2}}{c d}}}{c d^{2} - a e^{2}}\right ) -{\left (3 \, c^{2} d^{2} e^{2} x^{2} + 23 \, c^{2} d^{4} - 35 \, a c d^{2} e^{2} + 15 \, a^{2} e^{4} +{\left (11 \, c^{2} d^{3} e - 5 \, a c d e^{3}\right )} x\right )} \sqrt{e x + d}\right )}}{15 \, c^{3} d^{3}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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